General Relativity: Difference between revisions
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Einstein's [http://en.wikipedia.org/wiki/General_relativity General Relativity] is a theory of gravity which is based on the [http://en.wikipedia.org/wiki/Equivalence_principle Equivance Principle] that asserts that a uniform gravitational field (next to an infinite flat massive body) is indistinguishable from a uniform accelleration. | Einstein's [http://en.wikipedia.org/wiki/General_relativity General Relativity] is a theory of gravity which is based on the [http://en.wikipedia.org/wiki/Equivalence_principle Equivance Principle] that asserts that a uniform gravitational field (next to an infinite flat massive body) is indistinguishable from a uniform accelleration. | ||
:<math>\nabla \cdot \mathbf{A} = - 4 \pi G\rho</math> | :<math>\nabla \cdot \mathbf{A} = - 4 \pi G\rho</math> | ||
Latest revision as of 05:10, 9 May 2024
1 Introduction
Einstein's General Relativity is a theory of gravity which is based on the Equivance Principle that asserts that a uniform gravitational field (next to an infinite flat massive body) is indistinguishable from a uniform accelleration.
- $ \nabla \cdot \mathbf {A} =-4\pi G\rho $
2 Coordinate Systems
We will use the Einstein Notation. Consider Cartesian space in $ \mathbb {R} ^{2} $, covered by Cartisian coordinates $ (x^{1},x^{2})\, $. Pythagorous can be used to give the squared differential displacement:
- $ ds^{2}=(dx^{1})^{2}+(dx^{2})^{2}\, $
Now consider a general curvilinear coordinate system (CS) $ (y^{1},y^{2}\,) $. Since the lines of the CS are neither parallel nor perpendicular, we form the same quantity:
- $ ds^{2}=g_{11}(dy^{1})^{2}+2g_{12}dx^{1}dx^{2}+g_{22}(dy^{2})^{2}\, $
In general the metric tensor $ \mathbf {g} \, $ is a function of position. The terms $ g_{11}\, $ and $ g_{22}\, $ describe the relative spread of the axes, while $ g_{12}\, $ describes how the axes are not perpendicular.
A particular geometry is called Flat if it can be described by a Euclidian geometry. In general, curved manifolds (such as the surface of a sphere) require a more complex metric.
Example: Metric Tensor in Polar Coordinates
Consider polar coordinates in Euclidean space:
- $ x=r\cos(\theta ),\;y=r\sin(\theta ) $
The differential distance is given by:
- $ \mathrm {d} s^{2}=\mathrm {d} x^{2}+\mathrm {d} y^{2}=\mathrm {d} r^{2}+r^{2}\mathrm {d} \theta ^{2}\, $
which shows the components of the metric tensor are:
- $ g_{rr}=1,\;g_{\theta \theta }=r^{2},\;g_{r\theta }=0 $
Transformation
Now consider a general transformation between two general CS $ x, $ and $ y, $, and a scalar field $ \phi , $. The scalar field does not depend on the CS used, thus:
- $ \phi (y)=\phi (x); $.
Now,
Contravariant vector transformation:
- $ V^{n}(y)={\frac {\partial y^{n}}{\partial x^{m}}}V^{m}(x) $
Covariant vector transformation:
- $ V_{n}(y)={\frac {\partial x^{m}}{\partial y^{n}}}V_{m}(x) $
Derivative of a Tensor
Scalar
Consider a scalar field $ \phi \, $. Clearly the value of the field at any point P is independent of the CS used to label P. If the field is constant on one CS, will be constant in any CS. Note that:
- $ {\frac {\partial \phi }{\partial x^{m}}} $
is a vector.
Vector
Now consider a constant vector field $ \mathbf {V} $ in flat space, in the Cartesian CS. The covariant components of $ \mathbf {V} $ are also constant - that is, the projections on the axes:
- $ {\frac {\partial V_{m}}{\partial x^{n}}}=0 $.
If the vector field is now labelled by a general curvilinear CS, we see that the components of the vectors now change over position, even if the vector is constant, because the CS is not "constant":
- $ {\frac {\partial V_{m}}{\partial x^{n}}}=0 $.
Moreover:
- $ {\frac {\partial V_{m}(x)}{\partial x^{n}}}=0\Rightarrow {\frac {\partial V_{m}(y)}{\partial y^{n}}}=0 $
which states that vectors do not transform as tensors under a CS change.
Covariant Derivative
We would like to find a new definition of a derivative that maps a vector to a vector, and a tensor to a tensor. "Covariant" in this context means the quantity is independent of the CS chosen. Suppose there exists:
- $ T_{mn}(x)={\frac {\partial V_{m}}{\partial x^{n}(x)}} $
So:
- $ T_{mn}(y)={\frac {\partial x^{r}}{\partial y^{m}}}{\frac {\partial x^{s}}{\partial y^{n}}}T_{sr}(x)={\frac {\partial x^{r}}{\partial y^{m}}}{\frac {\partial x^{s}}{\partial y^{n}}}{\frac {\partial V_{r}(x)}{\partial x^{s}}} $
Now compare with (expanding):
- $ {\frac {\partial V_{m}(y)}{\partial y^{n}}}={\frac {\partial }{\partial y^{n}}}{\frac {\partial x^{r}}{\partial y^{m}}}V_{r}(x)={\frac {\partial x^{r}}{\partial y^{m}}}{\frac {\partial V_{r}(x)}{\partial y^{n}}}+{\frac {\partial }{\partial y^{n}}}{\frac {\partial x^{r}}{\partial y^{m}}}V_{r}(x) $
The first term is equal to $ T_{mn}(y)\, $, but we have a second term, which we denote by $ \Gamma ^{r}{}_{mn}\, $
Hence in gernal we need to differentiate in a way to cancel the second term to get back a tensor:
- $ \nabla _{p}T_{mn}={\frac {\partial T_{mn}}{\partial y^{p}}}+\Gamma ^{r}{}_{pm}T_{rn}+\Gamma ^{r}{}_{pm}T_{mr} $
The Christoffel Symbols can be found from the metric tensor:
- $ \Gamma ^{a}{}_{bc}(y)={\frac {1}{2}}g^{ad}\left({\frac {\partial g_{dc}}{\partial y^{b}}}+{\frac {\partial g_{db}}{\partial y^{c}}}-{\frac {\partial g_{bc}}{\partial y^{d}}}\right) $
Parallel Transport and Curvature
Space is called "flat" (like Cartesian space) when it is possible to choose a CS such that the covariant derivavtive of the metric tensor is everywhere zero:
- $ \nabla _{r}g^{mn}=0 $ that is the metric tensor reduces to the delta function: $ g_{mn}=\delta _{mn}\, $
A space may be flat in some areas, but there may be curvature at other points. It is always possible to choose a CS such that at a given point, the derivavtive of the metric is zero - that is in, a small enough neighbourhood of any point of a continuous, differentiable space looks flat.
Consider a vector V moving from point A to B over a curve, whilst remaining parallel to itself. This is notion of parallel transport, and can be extended to general nonflat spaces. The covariant derivavtive:
- $ \nabla _{s}V^{m}={\frac {dV^{m}}{ds}}+\Gamma ^{m}{}_{np}V^{n}{\frac {dx^{p}}{ds}} $
If a vector is parallel transported such that the covariant derivative is always zero, the vector follows a geodesic; geodesics are in some sense the "straightest" lines that exist in the manifold. For example: all straight lines in flat 2D space are geodesics; on the surface of a sphere, all great circles are geodesics.
The geodesic condition is:
- $ {\frac {d^{2}x^{m}}{ds^{2}}}+\Gamma ^{m}{}_{np}{\frac {dx^{n}}{ds}}{\frac {dx^{p}}{ds}}=0 $